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Statistics 11 Online
OpenStudy (anonymous):

Please help!!!! Statistic... Assume that the readings on the thermometers are normally distributed with a mean of 0 and standard deviation of 1.00 Celsius. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P97, the 97th percentile. This is the temperature reading separating the bottom 97% from the top 3%. Thank you!!! :D

OpenStudy (anonymous):

I already have the graph.

OpenStudy (anonymous):

@jim_thompson5910 Hi Jim, Quick question I know you might have the answer. Why the Z score is =1.88? Please help! ;)

jimthompson5910 (jim_thompson5910):

do you have a calculator?

OpenStudy (anonymous):

Yes! the TI-30xiis

jimthompson5910 (jim_thompson5910):

hmm don't know if that calc has the statistics tools you need in this case

OpenStudy (anonymous):

I don't think so, because the teacher didn't emails us the formula for us to use it on the calculator, she usually does.

jimthompson5910 (jim_thompson5910):

ok then you'll have to use a table

OpenStudy (anonymous):

I we have to use the table.

OpenStudy (anonymous):

Yes, she sent us the whole table. I have it with me.

jimthompson5910 (jim_thompson5910):

ok can you post it here please

OpenStudy (anonymous):

Ok!

OpenStudy (anonymous):

http://wps.aw.com/aw_triola_stats_series/ It's the 6th and 7th page.

jimthompson5910 (jim_thompson5910):

which book are you using?

OpenStudy (anonymous):

Elementary Statistic, Mario F. Triola 11th Edition

jimthompson5910 (jim_thompson5910):

look at the table on pg 6, look for the value 0.97 or something close to it Notice how 0.9699 is very very close to it This value is found at the row starting with 1.8 and it's in the column that starts with .08 So this means that P(Z < 1.88) is roughly 0.9699 according to the table So P(Z < 1.88) is roughly 0.97

OpenStudy (anonymous):

Ok, I looked the table and I saw that. But do I know that it will be 1.88? Do I have to use a formula to do it so first?

jimthompson5910 (jim_thompson5910):

no, the row 1.8 combines with the column .08 to get 1.88

jimthompson5910 (jim_thompson5910):

no formula is needed

OpenStudy (anonymous):

Yes, I undertand tha part..

OpenStudy (anonymous):

But the won't give this answer. Z=1.88. I have to figure it out..

OpenStudy (anonymous):

How you find this answer? I know it might be a silly question.

jimthompson5910 (jim_thompson5910):

The answer is 1.88 degrees Celsius since the mean is 0 degrees Celsius and the std deviation is 1 degree Celsius

jimthompson5910 (jim_thompson5910):

not sure what you're asking exactly

OpenStudy (anonymous):

I know is confusing through this way..

OpenStudy (anonymous):

I go to the table and look .97 and the Z score is something else.

jimthompson5910 (jim_thompson5910):

let me see

jimthompson5910 (jim_thompson5910):

which page are you looking at?

OpenStudy (anonymous):

I got the wrong, they gave me the right one which is 1.88. But once you go and look for the z on the tables is different.. You understand what I mean, now?

OpenStudy (anonymous):

Answer**

OpenStudy (anonymous):

Page 7

OpenStudy (anonymous):

Ok, I think I know what you meant.... So i have to look to the clsest .97 which .9699 on the table.... I am sooooooooo DUMMY!!

jimthompson5910 (jim_thompson5910):

no you're not, but I'm glad you're starting to see what I mean

OpenStudy (anonymous):

OMGoshhhh!!! It took almost 3 days to figure it out

jimthompson5910 (jim_thompson5910):

that's ok, as long as you get it now, that's all that matters really

OpenStudy (anonymous):

Thank so much!!! You lifesaver!!! jejejeje!!

jimthompson5910 (jim_thompson5910):

you're welcome

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