Question

Given the functions f (x) = x^2 - 6x + 5, g(x) = -7x + 8 find the value of x at which the graphs have parallel tangent lines.

Not sure how to get the answer for this, I assume I need to get the derivative of each function, but not sure where to go from there.

Answer 1

\(g\) is a line with slope \(-7\) so your question can be interpreted as
"find the value of \(x\) for which \(f'(x)=-7\)"
tale the derivative, set it equal \(-7\) and solve

Answer 2

so x=1/2

Answer 3

wait thats wrong

Answer 4

satellite73 please help with my open question

Answer 5

-13

Answer 6

i don't know, i didn't do it
\[f'(x)=2x-6\]
\[2x-6=-7\]
\[2x=-1\]
\[x=-\frac{1}{2}\] is what i get

Answer 7

i wrote down 7, not -7 lol.

Answer 8

yes haha, i forgot to change my 6 lol.

Answer 9

good now right?

Answer 10

perfect thanks. : )