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Why does: ln[(tan(x)^sinx] = sinx(ln tanx) ?
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This is using the log power rule. (rule 3 -- http://www.purplemath.com/modules/logrules.htm )
f\[\ln[(tanx) ^{sinx}] = (sinx)(lntanx)\]
mathteacher, but this is ln?
ln(x) = log (base e) of x
is that even english?
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ah ok, thanks mathteacher!
Sorry, I should have used math notation: \[\huge \ln(x) = \log_e(x)\] In other words, yes, the log rules all work for ln(x).
alright, thanks a lot!
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