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Mathematics 12 Online
OpenStudy (anonymous):

Why does: ln[(tan(x)^sinx] = sinx(ln tanx) ?

OpenStudy (mathteacher1729):

This is using the log power rule. (rule 3 -- http://www.purplemath.com/modules/logrules.htm )

OpenStudy (anonymous):

f\[\ln[(tanx) ^{sinx}] = (sinx)(lntanx)\]

OpenStudy (anonymous):

mathteacher, but this is ln?

OpenStudy (mathteacher1729):

ln(x) = log (base e) of x

OpenStudy (anonymous):

is that even english?

OpenStudy (anonymous):

ah ok, thanks mathteacher!

OpenStudy (mathteacher1729):

Sorry, I should have used math notation: \[\huge \ln(x) = \log_e(x)\] In other words, yes, the log rules all work for ln(x).

OpenStudy (anonymous):

alright, thanks a lot!

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