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Chemistry 11 Online
OpenStudy (anonymous):

26.5g C16H34 88.0g O2 Which is the limiting reagent?

OpenStudy (australopithecus):

Write out the reaction they are undergoing and convert both masses to moles. The limiting reagent will provide the least amount of product

OpenStudy (australopithecus):

so which ever reagent gives you the smallest amount of moles of product is the limiting reagent

OpenStudy (anonymous):

so like 26.5 g ( I mol C16 H34)/ 226.446 g C26 H34) ???? And the same with O2?

OpenStudy (australopithecus):

26.5g/226.446 = 0.117mol now convert to product, In this case I will convert to CO2 (0.117mol/2)*32 = 1.872mol now do this with O2 and compare the amount of moles you get. The Reactant that gives you the least amount of moles will be your limiting reagent

OpenStudy (anonymous):

hmm okay!!! makes more sense.

OpenStudy (australopithecus):

see your other question

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