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Solve for g
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\[T=2\pi \sqrt{L/g}\]
1st divide both sides by 2pi
T/2pi=squareroot(L/g)?
how can we get rid of the square root
By squaring both sides? Which would look like this: Squareroot (T/2pi)= L/g
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you said it squaring not taking square root
(T/2pi)^2= L/g
how can we make g on top
g=(T/2pi)^2/L? I'm not really sure sorry. :(
(T/2pi)^2= L/g multiply by g g*(T/2pi)^2= L
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Oh. I think I had a brain blank. You multiply g as your trying to get rid of it from the right side.
g*(T/2pi)^2= L then divide by (T/2pi)^2 g = L/(T/2pi)^2
Thanks so much for the help! I think I get how its done now :D
you still not done though L/(T/2pi)^2=1/(T^2/(4*PI^2))=L*4*Pi^2/T^2
I think I can calculate from here. It'll just take me some time :P
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