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Mathematics 17 Online
OpenStudy (thesecret20111):

Solve for g

OpenStudy (thesecret20111):

\[T=2\pi \sqrt{L/g}\]

OpenStudy (anonymous):

1st divide both sides by 2pi

OpenStudy (thesecret20111):

T/2pi=squareroot(L/g)?

OpenStudy (anonymous):

how can we get rid of the square root

OpenStudy (thesecret20111):

By squaring both sides? Which would look like this: Squareroot (T/2pi)= L/g

OpenStudy (anonymous):

you said it squaring not taking square root

OpenStudy (anonymous):

(T/2pi)^2= L/g

OpenStudy (anonymous):

how can we make g on top

OpenStudy (thesecret20111):

g=(T/2pi)^2/L? I'm not really sure sorry. :(

OpenStudy (anonymous):

(T/2pi)^2= L/g multiply by g g*(T/2pi)^2= L

OpenStudy (thesecret20111):

Oh. I think I had a brain blank. You multiply g as your trying to get rid of it from the right side.

OpenStudy (anonymous):

g*(T/2pi)^2= L then divide by (T/2pi)^2 g = L/(T/2pi)^2

OpenStudy (thesecret20111):

Thanks so much for the help! I think I get how its done now :D

OpenStudy (anonymous):

you still not done though L/(T/2pi)^2=1/(T^2/(4*PI^2))=L*4*Pi^2/T^2

OpenStudy (thesecret20111):

I think I can calculate from here. It'll just take me some time :P

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