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OpenStudy (anonymous):
Are those s*cos and s*sin? s might be a coefficient.
OpenStudy (anonymous):
Are you doing things with vectors and parametric equations? s could be a parameter.
OpenStudy (anonymous):
It's definitely not a coefficient but it's for a projectile problem
OpenStudy (anonymous):
Does the letter 's' represent anything else in the problem?
OpenStudy (anonymous):
no it's used like this "The initial velocity is equal to the final velocity horizontally because there is zero acceleration horizontally (v₀ = v = 89.0m/scos54.0° = 52.3m/s).The horizontal range is:"
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OpenStudy (anonymous):
Oh!, the s is in the denominator of the unit for velocity m/s.
OpenStudy (anonymous):
oh my goodness you're a genius!
OpenStudy (anonymous):
It should be written like this:
\[\large v = 89.0\frac{m}{s}*cos(54.0º)\]
OpenStudy (anonymous):
how did I miss that wow
OpenStudy (anonymous):
Thank you!!
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OpenStudy (anonymous):
You're welcome. I'm glad it didn't turn out to be 3-dimensional parametric vector equations like I first thought.