Question

Formula of nitrate of a metal is \(\Large{M(NO_3)_3}\); the formula of its pyrophosphate is :-

A. \(\Large{M_3(P_2O_7)_4}\)
B. \(\Large{M(P_2O_7)_2}\)
C. \(\Large{M_2(P_2O_7)_3}\)
D. \(\Large{M_4(P_2O_7)_3}\)

Answer 1

@Chlorophyll @chemistry_help plz help:)

Answer 2

Here is a picture of pyrophosphate

Answer 3

First determine what the charge of NO3 is

Answer 4

@Australopithecus can u plz help me with my chem question?

Answer 5

its -1,

so you have -3

thus M has to have a charge of +3 to render the molecule neutral

Answer 6

metals always loses electrons therefore it must have a positive charge.

Answer 7

notice that Pyrophosphate has a charge of -4

Answer 8

Formula: P2O7^4−

Answer 9

What ratio of M and pyrophosphate do you need to render a neutral molecule

Answer 10

HINT: Remember 4*3 = 12

Answer 11

do you follow?

Answer 12

sorry i m confusing :(

Answer 13

confused*

Answer 14

NO3 has a charge of -1
(NO3)3 means that there are three groups of this polyatomic ion thus there is a total charge given by them of -3

so you have

(NO3)3 -3

thus M has to have a charge of +3 because the molecule is neutral.

We now know the charge of M is +3
We also know that pyrophosphate has a charge of -4

thus we need to figure out the ratio of M to Pyrophosphate to render a neutral compound

Answer 15

I gave you the hint 3*4 = 12
think about it, you need to have an amount of M that gives a charge equal to the amount of pyrophosphate

Answer 16

@jiteshmeghwal9 Do you agree up the charge of M is +3?

Answer 17

yes

Answer 18

Since from the negative charge, we have P2O7 charge is -4!

Answer 19

-> By the rule, total charge must be neutral, how do we balance between -4 and +3, so they will cancel out?

Answer 20

I have not studied Chemistry other than Atomic Structure so sorry i can't do this man. I'm going

Answer 21

+3 * 4 = 12
-4 * 3 = 12

so we need 4 molecules of M
and we need 3 molecules of Pyrophosphate

thus we have

M4(P2O7)3

Answer 22

+3 * 4 = +12 charge
-4 * 3 = -12 charge