Question

how many moles are present in 1.51 x 10^23 molecules of MgCL2

Answer 1

Do you know the formula for calculating no. of moles in a given compound?

Answer 2

well yes, but I think one of my steps is wrong

Answer 3

use avagadros number

Answer 4

I found the molar mass of MgCl2 = 95.205

but I kind of guessed to mutiply the 1.51 x10^23 by 6.022 x10^23 then by 95.205 which was wrong.

Answer 5

How do you find mole from mass and molar mass?

Answer 6

Molar mass is correct.

Answer 7

Yes the second guess is wrong.

Answer 8

Let me think of this formula :

\[\text{No. of moles} = \frac{\text{Mass in grams}}{\text{Molecular Mass}}\]

Answer 9

avagadros number = 6.02214129(27)×10^23/mol

1.51 x 10^23 molecules / 6.02214129(27)×10^23 molecules/mol

Answer 10

Can you calculate this,,,,@Lanik what @Australopithecus had given ... She has made your way easier..

Answer 11

sorry avagadros number is
6.022141*10^23

Answer 12

but yeah it usually has unites of 1/mol

Answer 13

Why you wrote ... (27) there ?

Answer 14

if you divide by it, it will convert molecules to mole

Answer 15

I cut and pasted it from wikipedia

Answer 16

lol got it :)

Answer 17

Cut? it must be copied ;)

Answer 18

okay i got 2.50747 x 10^45

Answer 19

Calculator?

Answer 20

yes

Answer 21

alright ...

Answer 22

So where are the units? Can you name the unit of that.?

Answer 23

Thats a wrong answer. doesnt match. SOOO….

Answer 24

Was it the final step...?

Answer 25

1.51 x 10^23/6.022141*10^23
=
0.25mol

Answer 26

You have to use 95.05 g also.. So the above step was not the "last" step

Answer 27

10^{23} will get cut..... from where did you get 10^45 lanik?

Answer 28

thats so werid I did the exact same thing and I got the other answer

Answer 29

What is the answer given @Lanik (I mean the answer in the book)