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Algebra
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State whether the statement x_n (is not equal to) x_n-1 is always, sometimes or never true if x_n = f(x_n-1). Explain.
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it is clearly not always true
why?
\(f\) can be any function right? so you could say \(f(x)=x+1\) and \(x_1=1\) so \(x_2=1+1=2\) and \(2\neq 1\)
ohhh. okay thanks
but it could be true, for example if \(f(x)=3\) and \(x_1=1\) then \(f(1)=3\) making \(x_2=3\) and also \(f(3)=3\) so \(x_3=3\) and so on
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so sometimes but not always. okay thanks :)
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