Question

solve for x??? this is exponential decay!!
y = ae−bx

Answer 1

So...
\[
y=ae^{-bx}
\]?
If so:
\[
\frac{y}{a}=e^{-bx}\implies\\
\ln\left(\frac{y}{a}\right)=-bx\implies\\
-\frac{\ln\left(\frac{y}{a}\right)}{b}=x
\]

Answer 2

WOW! I spent an hour on this problem and still could not solve it. You are awesome!
Thank you

Answer 3

Sure thing!