Question

find the derivative of the function, h(x)=2/(3x)^2

Answer 1

\[
h(x)=\frac2{(3x)^2}=\frac2{9x^2}=\frac29x^{-2}\\
h'(x)=\frac29(-2x^{-3})=-\frac4{9x^2}
\]

Answer 2

is this a rule>? @oldrin.bataku

Answer 3

@jessiedeee I used the fact that the derivative of the product of a constant and a function is equivalent to the product of said constant and the derivative of said function, i.e. d/dx [ku] = k d/dx [u]. I then used the power rule, i.e. d/dx x^n = n x^(n-1)

Answer 4

ohhh ok I see thankyou:)@oldrin.bataku

Answer 5

thats not rite

Answer 6

@Dwade03 ?

Answer 7

we need to use the quotient rule for this problem

Answer 8

@Dwade03 how would you use the quotient tule for this?

Answer 9

because u have a function being divided..in this case its the (3x)^2

Answer 10

ohhh yeahhh! so in that case,
f(x)=2
g(x)=(3x)^2
?? right?
@Dwade03

Answer 11

yes sir