Question

\[\large \rm \lim_{x \to 0}{\sin(3x) \over x}\]

Answer 1

I have a feeling that we have to use\[\rm \large\lim_{x \to 0}{\sin(x) \over x} = 1\]

Answer 2

Squeeze theorem?

Answer 3

just multiply by 3/3

Answer 4

How about multiplying 3 to both numerator and denominator?\[\large \rm\lim_{x \to 0}{\sin(3x) \over 3x}\times 3\]Oh

Answer 5

Hehe, thanks!

Answer 6

welcome :)

Answer 7

Haha, nice hack. ;)