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MIT 6.002 Circuits and Electronics, Spring 2007 8 Online
OpenStudy (anonymous):

In the figure below, find the following. (Let emf1 = 23.0 V, emf2 = 14.0 V, and R = 21.0 Ω.) (a) the current in each resistor (b) the power delivered to each resistor

OpenStudy (anonymous):

OpenStudy (anonymous):

Current through each resistor :- I1-395.41mA , I2-172.62mA , I3-568.03mA

OpenStudy (anonymous):

Power delivered - Pr1-4.38W , Pr2-0.36W , Pr3-6.78W

OpenStudy (nurali):

Loop 1:- -14+23=28i1+(i1-i3)12 9=40i1-12i3-------(1) Loop 2:- 14=(i3-i1)12+21i3 14=33i3-12i1------(2) Solving (1) and (2) i1=395.4mA i3=568mA i2=(i3-i1) i2=172.6mA Now Power p1=i1^2*R=(395.4m)^2*28=4.38W p2=i2^2*R=(172.6m)^2*12=0.36W p3=i3^2*R=(568m)^2*21=6.78W

OpenStudy (nurali):

if correct please click best response

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