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How long will it take an investment to double in value if the interest rate is 8% compounded continuously?
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How long will it take an investment to double in value if the interest rate is 8% compounded continuously?
\[A=Pe ^{rt}\] P = principal amount (initial investment) r = annual interest rate (as a decimal) t = number of years A = amount after time t \[\frac{A}{P}=e ^{rt}=e ^{0.08t}=2\] Now you need to solve for t.
@kglaguardia Do you know how to solve for t?
\[2=ln e ^{0.08t}\]...lets you bring down the exponent so it would be \[2=0.08t \ln e\]...bring over the 0.08 and lne is equal to 1
\[e ^{0.08t}=2\] Taking natural logs of both sides gives: \[0.08t=\ln 2\] \[t=\frac{\ln 2}{0.08}\]
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right. forgot about the other side.
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