Question

find the absolute extrema of the function y=x^3-(3/2)x^2, [-1,2]

Answer 1

My answeres are f(-1)= -5/2
f(0)=0
f(1)= -1/2
f(2)=2
I just dont know which is the min and max

Answer 2

Refer to the attachment.

Answer 3

ok. got it

Answer 4

so are the mins and max the endpoints or the hills and valleys??