Question

x=t-1,y=t^3/2, 0 14 years ago

Answer 1

\[ds^2=dx^2+dy^2\]\[ds=\sqrt{dx^2+dy^2}=\sqrt{1+\frac{dy^2}{dx^2}}dx=\sqrt{1+(\frac{dy}{dx}})^2dx\]
Length of line\[\int\limits_{t=a}^{t=b}ds\]

\[\int\limits_{t=a}^{t=b}\sqrt{1+(\frac{dy}{dx}})^2dx\]

Answer 2

And you can change the bounds to be nice- in terms of x. That is,
x=t-1
so for t=a
change it to x=a-1

obviously a is actually 0 in your question

do the same for b

Answer 3

but this is wut i did last time

Answer 4

What's the problem, then?