Question

Use reduction of Order to find second solution.
t^2y''+2ty'-2y=0 y1(t)=t

Answer 1

I think u put y' = x -> y'' = 1 and y = x^2/2 + c

Then use the condition to calculate c. etc

Answer 2

um what? this is Differential Equations

Answer 3

Yes, I am reducing to two first order de's....

Answer 4

o well thats wrong y2'= v'(t) +v(t)

Answer 5

?

Answer 6

thats now how you solve reduction of order problems, you DONT need to split them up into 2 1st order Diff EQs

Answer 7

OK

Answer 8

Now I see, y1(t) = t is a solution, not an initial condition....duh.

Answer 9

So u have put y2 = v(t)t ->

y2'= v'(t) +v(t)

Is this where the problem is?

Answer 10

After subbing in the DE and simplifying I got

t^3v'' +4t^2v' = 0 and putting w =v' (so w' =v'') ->

t^3w' +4t^2w for a first order de.