An air capacitor is charged to a certain potential difference.it is then immersed in oil .What happens to its(a)capacitance(b)charge(c)potential.

Question

anonymous · Answer

Assuming it has a higher di-electric constant than air the capacitance will increase
Knowing this use formulae involving capacitance to check how it is affected in proportion to charge and voltage

anonymous · Answer

Usually oil has higher di-electric constant so as per the relation
$$C= \epsilon o*\epsilon r*A/d$$
increase in $$\epsilon r$$ increases capacitance

charge between the plates remains the same

and voltage reduces as per the relation
V=q/C