Question

An air capacitor is charged to a certain potential difference.it is then immersed in oil .What happens to its(a)capacitance(b)charge(c)potential.

Answer 1

Assuming it has a higher di-electric constant than air the capacitance will increase
Knowing this use formulae involving capacitance to check how it is affected in proportion to charge and voltage

Answer 2

Usually oil has higher di-electric constant so as per the relation
\[C= \epsilon o*\epsilon r*A/d\]
increase in \[\epsilon r\] increases capacitance

charge between the plates remains the same

and voltage reduces as per the relation
V=q/C