Question

Write the balanced net ionic equation for the following
aluminium and potassium hydroxide,, yielding [Al(OH)4]^-1 and hydrogen gas

Answer 1

@Sheng @oOKawaiiOo

Answer 2

\[Al ^{+3} + KOH \rightarrow [Al(OH)_{4} ]^{-1} + H _{2}\]

NOW I NEED TO BALANCE IT BUT I DO NOT KNOW HOW

Answer 3

I don't think this will give a yeild of hydrogen gas.
If aluminium was to react with potassium hydroxide solution to form the tetrahydroxyaluminate complex no hydrogen would be produced and the equation wouldn't show the potassium as it is only a spectator ion in this reaction
The nett ionic equation should be;
\[Al ^{3+} + 4OH^{-} \rightarrow [Al(OH)_{4}]^{-1}\]

Answer 4

so why does the question said hydrogen gas is included in the products

Answer 5

I'm not sure, the only way for it to produce 1 mole of hydrogen would also cause it to produce 1 mole of oxygen (if the aluminium ions reacted with 6 moles of hydroxide solution rather than 4, resulting in 1 mole of oxygen and 1 mole of hydrogen as products along with the aluminium complex)

Answer 6

ok i really do not get this but thanku for helping

Answer 7

Answer

2Al(s) + 2K+(aq) + 2OH-(aq) + 6H2O(l) --> 2[Al(OH)4]-(aq) + 2K+(aq) + 3H2(g)

Answer 8

thats correct.

Answer 9

the answer that you have there is correct.

Answer 10

yes i know that but i got form another website and i do not exactly get how to do that

Answer 11

\[Al ^{+3} + KOH \rightarrow [Al(OH)4 ]^{-1} + K ^{+} + H _{2}\]

that is what i have up to now

then what do i do

@Becky_Becca

Answer 12

\[Al+3+K ^{+} OH ^{-} →[Al(OH)4]−1+K++H2\]