Question

solve 4^3p(4^2p-1=100

Answer 1

the p goes along with the exponents on both sides

Answer 2

so,
\[4^{3p}(4^{2p} - 1) = 100\]

Answer 3

also add the -1 to the second part

Answer 4

i ment along with the exponent 2p

Answer 5

ugh equation editor isn't working anymore

Answer 6

also ignore the last line I made a mistake and forgot to add a p

Answer 7

I dont know if I'm on the right track to solving it but I can't attempt to complete my solution because this site is buggy

Answer 8

well i am lost, all i know is that the aswer has to be 0.8644

Answer 9

Oh I made a stupid mistake

Answer 10

\[4^{3p}(4^{2p-1}) = 100\]
\[4^{3p+ 2p - 1} = 100\]
\[4^{5p - 1} = 100\]
\[4^{5p}4^{- 1} = 100\]
\[\frac{4^{5p}}{4^{1}} = 100\]
\[\frac{4^{5p}}{4} = 100\]
\[4^{5p} = 100(4)\]
\[\log_4{4^{5p}} = \log_4{100(4)}\]
\[5p = \log_4{100(4)}\]
\[p = \frac{\log_4{100(4)}}{5}\]

Answer 11

there is your solution

Answer 12

I wish I was better at algebra so I could solve that other problem but it probably required some crazy technique ha

Answer 13

thank you so much this problem was making me mad

Answer 14

well it isn't that hard of a problem, it is just application of some fundamental rules of logarithms and exponents

Answer 15

do you follow how I came to the solution?

Answer 16

If you do not understand part of my solution tell me which part and I will show you the rule I applied

Answer 17

to be honest no

Answer 18

do you not understand any of it?

Answer 19

I'm about to go to sleep so please be quick in your responses

Answer 20

its better u go to bed, i will just ask i class tomorrow. thanks again

Answer 21

Well I can explain the rules to you if you want

Answer 22

unless you take me for a poor teacher ha which I'm fine with