find f(x+h) where f(x)=x-3 and h(x)=x+2
Would it be f(x+x+2)?
So then (x-3)+(x-3)+2?
Can you still help me?
It says to simplify the answer if it needs it...but that's it :)
Can you do anything to reduce it, or is that it?
So it isn't like f(x+10) or something like that, where you can still solve it further?
it isn't f((x-3)^2)+2)
Usually if f(x)=2x+6 (say) then f(x+h) = 2(x+h) +6 and h(x) is irrelevant, Are you doing some beginning calculus and learning about limits?
it is the class before pre-calc...
In the form that you asked the question . F(x+h) = x+h -3
how?
I replaced the "x" in the original function with "x+h".
explain...?
\[f(x) = x- 3\] Here replace x with x + h
What answer were you trying to get for this question?
\[f(x+h) = (x+h) - 3\]
Are you sure your question is not this : Find f(x) + h(x) ??
Or even f(h(x))?
it is f(x+h)
Then my answer agrees with waterineyes
but why do I replace the x with x+h?
See, f(x) = x - 3 (it simply means that f(x) is function of x) See : for x = 1 f(x) = 1 - 3 = -2 for x = 2, f(x) = 2 - 3 = -1 for x = 3 f(x) = 3 - 3 = 0 Here you can see f(x) depends upon x.. As x changes f(x) changes...
And now f(x+h) means f(x+h) depends upon x + h: So to find it f(x) you have earlier, here if we add h to it then it will become function of x + h : So : replace x by x + h.. f(x) = x - 3 replace : f(x+h) = (x+h) - 3
ok...I think that I get it...
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