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Physics 18 Online
OpenStudy (anonymous):

14000kg of copper is heated using a heater with an effect of 1200W. The starting temperature is 20 degrees kelvin. After 8 minutes, the temperature is 120 degrees kelvin. What is the heat capacity of copper in J/(kg K)? What I get is: (1200 * 60 * 8) / (14000 * (120-20)) = 0.411 The answer *should* be 430 J/(kg K). Can anyone tell me what I should be doing? :)

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