√(x+1)-(x-1)
Could someone explain how that equation simplifies to 2√x?
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OpenStudy (calculusfunctions):
Is it\[\sqrt{(x +1)}-(x -1)\]
OpenStudy (anonymous):
I typed the question wrong √(x+1)^2-(x-1)^2
Could someone explain how that equation simplifies to 2√x
OpenStudy (calculusfunctions):
I thought as much!
OpenStudy (calculusfunctions):
So it's\[\sqrt{(x +1)^{2}-(x -1)^{2}}\]Is this correct?
OpenStudy (anonymous):
Yes
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OpenStudy (calculusfunctions):
OK so do you know how to simplify the expression inside the root? You have two options: i). expand and collect like terms, or ii). factor by difference of squares method.
Choose a method.
OpenStudy (anonymous):
I'm okay with both. Whatever simpler to explain would be nice.
OpenStudy (calculusfunctions):
Both are simple. your choice.
OpenStudy (anonymous):
Collect like terms please then
OpenStudy (calculusfunctions):
OK then, do you know how to do that?
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OpenStudy (anonymous):
Is 4x correct?
OpenStudy (calculusfunctions):
Yes! so then we have\[\sqrt{4x}\]Do you know the next step to simplify this?
OpenStudy (anonymous):
Sqrt 2*2*x?
OpenStudy (calculusfunctions):
\[\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\]
OpenStudy (calculusfunctions):
So then by this rule\[\sqrt{4x}=\sqrt{4}\sqrt{x}\]Correct?
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