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Calculus: Find the derivative. Given the equation is s(t)=t^4-16t^2+5 For what values of t is v(t)=0
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\[t ^{4}-16t ^{2}+5\]
\[4t ^{3}-32t\]
Diff of s(t) is v(t)
v(t)=ds/dt=4t^3-32t=0 thus, \[4t ^{3}-32t=0\] \[4t(t ^{2}-32)=0\]
sorry last one is \[4t(t ^{2}-8)=0\]
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either t=0 or t^2-8=0 either t=0 or t^2=8 either t=0 or t=+sqrt(2) or t=-sqrt(2)
wait i got thx
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