Question

help please!
4Na+ZrCl4→Zr+4NaCl
Calculate the amount of zirconium produced (in kg) if a reactor were charged with 111 kg ZrCl 4 and 11.1 kg Na .

Answer 1

nvm i worked it out.
4Na = 91.96 g/mol
11100(grams from kgs) /91.96 = 120.7 Moles of Sodium in 11.1Kg. This is the limiting re-agent.
so 4 moles of Na per 1 of Zr. 120.7 * 91.22 = 11010.25 (divide by 1000 into kg)
= 11.01
correct me if im wrong?

Answer 2

you are very close, the correct answer is 11.005..
and good luck for edx

Answer 3

haha thanks :) and yeah i just rounded it up ;)