how do I solve for "p"
(-p+10p+9)/(p^2+9)=0

Question

how do I solve for "p"  
(-p+10p+9)/(p^2+9)=0

anonymous · Answer

the bottom half is actually (p^2+9)^2

anonymous · Answer

tha answer p=-1

anonymous · Answer

@gaby6 http://openstudy.com/code-of-conduct

tkhunny · Answer

Interestingly, and perhaps surprisingly, the denominator doesn't matter at all.  It is ALWAYS positive and doesn't do anything concerning whether the entire expression is zero (0).  Your task, then, is noly to find when the Numrator is zero.

anonymous · Answer

if I set the numerator to 0, i still can't figure it out, brain fart here. I know the answer is $$5\pm \sqrt{34}$$ but im not sure how to get that

tkhunny · Answer

You haven't typed it correcty.  Should there be a p^2 in there?

Check the problem statement and give it another go.

anonymous · Answer

$$\frac{ -p^2+10p+9 }{ (p^2+9)^2 }$$ that is the equation, i am trying to find the critical number for that, the equation is the derivative of (p-5)/(p^2+9)

anonymous · Answer

For -p^2+10p+9, the roots are 5±√(136)