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OpenStudy (unklerhaukus):
\[b^1=b\qquad\Rightarrow\qquad \log_bb=1\]
jhonyy9 (jhonyy9):
can you rewrite it here please ?
jhonyy9 (jhonyy9):
log3 3 + log3 x =5
so do you know the property of logarithms ?
jhonyy9 (jhonyy9):
and loga a = ?
jhonyy9 (jhonyy9):
so if loga a=1 than how will be your exercise ?
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jhonyy9 (jhonyy9):
so than log3 3=1
yes ?
jhonyy9 (jhonyy9):
than will be
1+log3 x=5
jhonyy9 (jhonyy9):
add to both sides -1
1+(-1) +log3 x=5-1
log3 x=4
ok ?
jhonyy9 (jhonyy9):
how can you rewriting 4 using log3 3 ?
jhonyy9 (jhonyy9):
so you know that logx y^2 =2logx y
this will help you sure
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jhonyy9 (jhonyy9):
so when there are logarithm base x of x on indifferent exponent so than the exponent coming in the first place how you see there that the exponent of y is
logx y^2 = 2logx y
jhonyy9 (jhonyy9):
@surdawi can you help to make understanding this all
OpenStudy (unklerhaukus):
\[\log_bb=1\qquad\Rightarrow\qquad\log_33=1\]
\[\log_3 3 + \log_3 x =5\qquad\Rightarrow\qquad 1 + \log_3 x =5\]