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OpenStudy (anonymous):
Simplify the expression.
(–2 – 2i)(–4 + 6i)
>8 – 4i
>8 – 12i
>20 – 4i
>–4 – 4i
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OpenStudy (anonymous):
Do you know the value for i (iota) ?
OpenStudy (anonymous):
just multiply everything and you should get the answer (i*i=-1)
OpenStudy (unklerhaukus):
\[\quad(–2 – 2i)(–4 + 6i) \]
\[=-2(–4 + 6i) -2i(-4+6i)\]
OpenStudy (anonymous):
\[\large{(-2-2i)(-4+6i)}\]
\[\large{-2(-4) -2i(-4) -2(6i) -2i(6i)}\]
\[\large{8 + 8 i - 12 i -12i^2}\]
OpenStudy (anonymous):
>–4 – 4i
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OpenStudy (anonymous):
Now since : \[\large{ i = \sqrt{-1} }\]
Therefore, \[\large{i^2 = (\sqrt{-1})^2 = -1 }\]
OpenStudy (anonymous):
Solving this we get : 8 - 4i - 12 = -4-4i
OpenStudy (anonymous):
Therefore the answer is : >-4-4i
OpenStudy (anonymous):
thank you all so much, i've got it now! @SheldonEinstein @surdawi
OpenStudy (anonymous):
Nice!
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OpenStudy (unklerhaukus):
mistake !
OpenStudy (anonymous):
20 -4i
OpenStudy (anonymous):
Sorry it will be : \[\large{8 + 12 - 4i = 20 -4i}\]
OpenStudy (anonymous):
I am REALLY VERY VERY SORRY for that... Thanks @UnkleRhaukus for pointing it out.
OpenStudy (unklerhaukus):
\[-12i^2=+12\]
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OpenStudy (anonymous):
Yeah
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