Help! Logarithmic functions
im saying use the definition of the logarithm to rearrange the equation and solve for x
\[\log_{3}(3) + \log_3(x) = 5\\ \log_{3}(3x) = 5 \\ 3^5 = 3x \\ \frac{3^5}{3} = x \\ 3^4 = x \\ 81 = x\]
Yes, I'm here :)
If you have any questions, let me know
you had reached \[\log_3 x=4\]already, now applying the definition of the logarithm \[\log_3 x=4\qquad\Rightarrow\qquad x=3^{4}\]\[\qquad\qquad\qquad \qquad \qquad \quad=3\times3\times3\times3\]
81
yep
@Hero, your amazing, by the way! Oh, and Thanks so much @UnkleRhaukus I really, sincerely, appreciate the help from both of you!
if you wanted to check your solution \(x=3^4=81\) just plug into \[\log_{3}(3) + \log_3(x) = 5\] see get \[\log_{3}(3) + \log_3(3^4) = 5\]\[\log_{3}(3) + 4\log_3(3) = 5\]\[\qquad\qquad\quad1+4=5\]
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