please help me solve
45 degrees since
Pi/4
can you please explain to me how you got that?
|dw:1351091765743:dw|notice that \[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] which we remember from the triangle
simple \[\sqrt{2}/2=1/\sqrt{2}\] it will affect only if the value is out of range
what are you talking about? confused the answer is pi/4 how did you get that?
can u answer my simple questions...........?
which is?
do u know about domain and range of sin^-1(x)???????
no
thats y u r getting confused in values
do u want me to tell about it right now:)
i just want to know how you got that answer
sin x is basicaly defined for all values of x but -1<sin x<1 happens always when we define sin^-1 x it is a inverse or we can say just opposite to the sinx which is defined for -1<x<1 and answer lies anywhere so a basic principle regien is defined and all other area is called general area so we knoww that sin 45 = 1/\[\sqrt{2}\] so sin -1 x = 45 degree or pi/4 radians in principal region.............k
:)
thank u first time i feel that i deserve it.lolz:D
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