Question

HELP!! How can I factor x^3-4x^2+x+6? I tried factor by grouping and it didnt work.

Answer 1

try -1

Answer 2

\[f(-1)=\]

Answer 3

if its a factor then\[(x+1)(x+-5x+6)\]

Answer 4

\[(x+1)(x^2-5x+6)\]

Answer 5

Could You explain please?

Answer 6

f(-1) =0

Answer 7

do you understand that\[f(-1)=0\]
implies x=-1 is a factor

Answer 8

o okay so we find the zeros of \[x ^{3} -4^{2} +x+6\] ?

Answer 9

or wait is it (x-3)*(X-2)*(x-1)?

Answer 10

yes but x+1 not x-1, how do you find it

Answer 11

this is how i do it \[(x+1)(x^2+bx+6)\]
so the b is any term that has an x^2 in the equation wich is -4 and we \[1+b=-4,b=-5\]

Answer 12

I just broke it up into three parts thanks for the help :)