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A kite 50ft above the ground moves horizontally at a speed of 8ft/s. At what rate is the angle between the string and the horizontal decreasing when 300ft of string has been let out?
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d = r •t t = d / r r = d / t Hope this helps, because these are the formulas.
still dont get how to set up the equation
300ft is the distance. and 8ft/s is the time, right?
correct
So, use r = d / t.
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300 / 8 = 37.5
derivate |dw:1351128473550:dw| \[\cos \alpha = \sqrt{a^2-b^2} / a \]
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