Question

closed

Answer 1

need more info

Answer 2

using real analysis?

Answer 3

?

Answer 4

@cagersallstar21, you should learn how to use latex

Answer 5

Perhaps this is what you meant:

\[\lim_{x \rightarrow -1} (x^2 - 1)\cos\left(\frac{1}{x+1}\right)\]

Answer 6

yepp that

Answer 7

as x approaches negative 1? yep

Answer 8

so how do i go about solving for that? because i believe its 0

Answer 9

Hint: multiply the fraction inside the cosine function by a factor of one. In this case, multiply it by \(\frac{(x-1)}{(x-1)}\)

Answer 10

Afterwards, continue finding the limit

Answer 11

alrighty

Answer 12

ok thanks

Answer 13

Did you find your limit?