Question

Help. Thanks.
http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg
You should be able to see it. Thanks:)

Answer 1

which one?

Answer 2

both. its 11 problems

Answer 3

help with whatever

Answer 4

any help is appreciated

Answer 5

they all use the distance formula, which is pythagoras

Answer 6

ok.

Answer 7

can u do the first as demonstration ill try the others?

Answer 8

page B number 1 i will do if i can read it properly

Answer 9

tnx

Answer 10

you have two points labelled A and B and no numbers to go with them so lets count

Answer 11

mm,ok

Answer 12

ok

Answer 13

to get from A to B you go 7 units right, and 2 units down
at least that is what i see

Answer 14

uh huh

Answer 15

let me verify

Answer 16

brb,counting

Answer 17

how did you get seven again?

Answer 18

we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2
by pythagoras, we get
\[d^2=7^2+2^2\]
\[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]

Answer 19

i counted how many steps i had to go the the right

Answer 20

did you count a or b?

Answer 21

i just counted them, i did not compute anything at all
just went "one, two, three, four, five, six, seven"

Answer 22

ok.

Answer 23

so we aare solving for the hypotnuese

Answer 24

ok, so sq rt 53 is about 7.2

Answer 25

yes in each case

that is the basis for the distance formula

Answer 26

like for number 3 on the same page, from A to B is 4 steps right, 4 steps up
distance is
\[d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]