Question

how do i find an equation for the tangent to the graph y = arcsecx at x=2

Answer 1

First find dy/dx = ???

Answer 2

Are you sure it's x=2?

Answer 3

yes thats what it says..

Answer 4

Oh... okay I was reading that wrong...
so can you find dy/dx = ???

Answer 5

Do you need help finding the derivative?

Answer 6

\[\frac{ 1 }{ \left| x \right| \sqrt{x^2-1}}\]?

Answer 7

yes

Answer 8

So you can find the slope using the derivative...
Find the slope of the line at x=2

Answer 9

slope = \(\large m = \frac{ 1 }{ \left| 2 \right| \sqrt{(2)^2-1}}=\frac{1}{2\sqrt3} \)

Answer 10

Now all you need is the y-coordinate when x=2
So you'll then have a point and a slope to write the equation of the tangent line in point-slope form

Answer 11

okay hang onn

Answer 12

well its the same thing lol