x^2+3x-28/(x+7)(x-4) (fraction)=-11

Question

anonymous · Answer

$$ \frac{x^2 +3x-28}{(x+7)(x-4)}=-11$$ 
Multiply both sides by [(x+7)(x-4)] to get
$$x^2 +3x-28 = -11[(x+7)(x-4)]$$
add 11[(x+7)(x-4)] to both sides and then simplify to a single quadratic equation to solve. 
Remember that x cannot two specific numbers

anonymous · Answer

Thats what I got in class but my teacher said "figure it out"

anonymous · Answer

$$ x^2 + 3x -28 +11x^2 +33x -28(11) =0$$
$$12x^2 +36x -28(12)=0$$  you can divide everything by 12 legally here
$$x^2 +3x -28 = 0 $$ 
$$(x+7)(x-4)=0$$ 
x=-7,4

anonymous · Answer

but you cannot divide things by 0 so the answer is undefined

anonymous · Answer

This is a bad problem, because if your math is correct you are dividing by zero.

anonymous · Answer

and some teacher you got there -confused

anonymous · Answer

Some of the examples in our textbook are wrong. We spend class time proving them wrong.

anonymous · Answer

The answer is no solution. Books do have typos and they drive me crazy, but sometimes the answer is no solution. Figure it out is pretty lame. You did figure it out. There wasn't a value of x that would make that equation work. Hence no solution.