Question

Write an equation and solve. Two times the difference of a number decreased by five is fourteen. What is the number?

Answer 1

2x-5=14

Answer 2

Solve for x:
2 x-5 = 14
Isolate terms with x to the left hand side.
Add 5 to both sides:
2 x+(5-5) = 14+5
Look for two terms that sum to zero.
5-5 = 0:
2 x = 14+5
Evaluate 14+5.
14+5 = 19:
2 x = 19
Solve for x.
Divide both sides of 2 x = 19 by 2:
Answer:
x = 19/2

Answer 3

hmm u sure ?

Answer 4

Isn't this saying 2(x -5)=14 ?

Answer 5

I was going to say that.

Answer 6

So x=12

Answer 7

haha, oh I didn't even look at the original question that hard just took her equation

Answer 8

Solve for x:
2 (x-5) = 14
Divide both sides by a constant to simplify the equation.
Divide both sides of 2 (x-5) = 14 by 2:
x-5 = 14/2
Divide 14 by 2.
14/2 = (2×7)/2 = 7:
x-5 = 7
Isolate terms with x to the left hand side.
Add 5 to both sides:
x+(5-5) = 7+5
Look for two terms that sum to zero.
5-5 = 0:
x = 7+5
Evaluate 7+5.
7+5 = 12:
Answer:
x = 12

Answer 9

Write an equation and solve. Five times the difference of a number subtracted from ten is forty. What is the number?

Answer 10

The question was confusingly worded IMHO

Answer 11

Solve for x:
5 (x-10) = 40
Divide both sides by a constant to simplify the equation.
Divide both sides of 5 (x-10) = 40 by 5:
x-10 = 40/5
Divide 40 by 5.
40/5 = (5×8)/5 = 8:
x-10 = 8
Isolate terms with x to the left hand side.
Add 10 to both sides:
x+(10-10) = 8+10
Look for two terms that sum to zero.
10-10 = 0:
x = 8+10
Evaluate 8+10.
8+10 = 18:
Answer:
x = 18

Answer 12

x=18