How would I graph the following line: 2x+3y= -3
find any 2 points on the line
if you write it as slope-intercept for it would be easier to graph. So: 3y= -2x -3 -> y= -2/3x -1 Then you would have the -1 as the y intercept and your slope would be -2/3. Hope I helped. :)
Why not work out where the line crosses the axes? Ie find the intercepts.
When x= 0, y = -1
but graphing these answeres only gives me one point though...
one point? it should give you a line.
Hmm, maybe I am doing something wrong. Let me try again..
Now put y=0 and x = -1.5. Two points.
it gives me a horizontal line. Would that be correct?
hmm, it should give you a negative sloped line.
That's what i initially thought, but when I imput it, that's what it gives me :(
hm, why don't you start at (0,-1) and then go down 3 and go right 2 and put a point, and keep going like that.
Let me try that and I'll let you know :)
sure :D
Like this? lol
uh, it's kinda wrong because the y-intercept is not exactly on (0,-1)
if you would push it up it would be ok
Okay let me try again.. :)
Better?
uh well, the y intercept is ok now but the slope is wrong. it should be 2 down and 3 right.
I think I FINALLY got it right :D Check it one last time please? :)
yes!!
YAY :D Finally! Thanks so much for your help! It's oh so appreciated :)
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