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Mathematics 6 Online
OpenStudy (anonymous):

How do i simplify?

OpenStudy (anonymous):

\[5x=\frac{ \log_{}4 }{ \log_{}3 }\]

OpenStudy (anonymous):

i need to solve for x.

OpenStudy (epikrebel):

Wow this basically reminded me to refresh up on my Algebra 2.

OpenStudy (anonymous):

i just don't know how i would divide 5 by log4/log3.

OpenStudy (anonymous):

This involves the properties of logarithm. @santw loga/logb = ?

OpenStudy (anonymous):

Wait!

OpenStudy (anonymous):

i tried that. my solutions manual gives a diff answer. @SheldonEinstein

OpenStudy (anonymous):

\[\large{\frac{log_b m}{log_b n} = log_b {m-n}}\]

OpenStudy (anonymous):

Is the answer 0 ?

OpenStudy (anonymous):

i'm trying to refrain from looking at the answers. but it shows me log4/5 log3? i'm lost.

OpenStudy (anonymous):

0.2524 @SheldonEinstein

zepdrix (zepdrix):

So they just divided both sides by 5..?

OpenStudy (anonymous):

Very near lol

OpenStudy (anonymous):

yes. @zepdrix i think my question is. how do you divide a fraction by a fraction?

OpenStudy (anonymous):

log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]

OpenStudy (anonymous):

\[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]

OpenStudy (anonymous):

|dw:1351139061407:dw|

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