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OpenStudy (anonymous):
How do i simplify?
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OpenStudy (anonymous):
\[5x=\frac{ \log_{}4 }{ \log_{}3 }\]
OpenStudy (anonymous):
i need to solve for x.
OpenStudy (epikrebel):
Wow this basically reminded me to refresh up on my Algebra 2.
OpenStudy (anonymous):
i just don't know how i would divide 5 by log4/log3.
OpenStudy (anonymous):
This involves the properties of logarithm. @santw loga/logb = ?
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OpenStudy (anonymous):
Wait!
OpenStudy (anonymous):
i tried that. my solutions manual gives a diff answer. @SheldonEinstein
OpenStudy (anonymous):
\[\large{\frac{log_b m}{log_b n} = log_b {m-n}}\]
OpenStudy (anonymous):
Is the answer 0 ?
OpenStudy (anonymous):
i'm trying to refrain from looking at the answers. but it shows me
log4/5 log3?
i'm lost.
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OpenStudy (anonymous):
0.2524 @SheldonEinstein
zepdrix (zepdrix):
So they just divided both sides by 5..?
OpenStudy (anonymous):
Very near lol
OpenStudy (anonymous):
yes. @zepdrix
i think my question is. how do you divide a fraction by a fraction?
OpenStudy (anonymous):
log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]
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OpenStudy (anonymous):
\[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]
OpenStudy (anonymous):
|dw:1351139061407:dw|
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