Question

PLEASE HELP
Find the absolute minimum value of f on the given interval.
f(x) = ln(x^2 + 3x + 4), [−2, 2]

Answer 1

find derivative of f(x)
then put f'(x) = 0

Answer 2

@Nazym are u here?

Answer 3

I got a wrong anser. -3/2

Answer 4

it is not a simple one
calculate f'(x)

Answer 5

\[f^'(x)=\frac{ 2x+3 }{ x^2+3x+4 }\]

Answer 6

\[x=\frac{ -3 }{ 2 }\]

Answer 7

@Jonask
she tell before that -3/2 is wrong answer

Answer 8

I got the same answer...Didn't work

Answer 9

calculate f''(x)
and put x=-3/2
check the value whether -ve or +ve

Answer 10

\[\left| -3/2 \right|\]

Answer 11

3/2=1,5

Answer 12

Jonask, it is the same thing...That's wrong(

Answer 13

try to calculate f''(x)

Answer 14

\[f(3/2)\]