Question

Two dice are rolled one after the other. Construct a sample space and find the probability that the sum of the dots on the dice total is a number greater than 3 if the second die is a 4

Answer 1

The sample space has 36 possible combinations of numbers. These can be set out in column form as follows:
6,6 5,6 4,6 3,6 2,6 1,6
6,5 5,5 4,5 3,5 2,5 1,5
6,4 5,4 4,4 3,4 2,4 1,4
6,3 5,3 4,3 3,3 2,3 1,3
6,2 5,2 4,2 3,2 2,2 1,2
6,1 5,1 4,1 3,1 2,1 1,1

Answer 2

I am getting the answer as 6 if the second die is 4
6 number greater than 3.
Therefore, 6/6 =1? Am I correct?

Answer 3

You are right in saying that there are 6 combinations with the second die having a 4 where the total of the dots is more than 3.
The sample space has 36 outcomes. Six of these outcomes fit the requirement in the question. The probability of success is the total number of outcomes that fit the requirement in the question ( 6 outcomes) divided by the sample space (36 outcomes).

Answer 4

@aemcgloi Do you understand?

Answer 5

I was contemplating the 36 but was confused by another example I was looking at! The 36 makes much more sense. Then my final answer would be 1/6

Answer 6

Yes, your answer is correct :)