Question

hyperbola help

Answer 1

how can you find b in \[\frac{x^2}{3^2} - \frac{y^2}{b^2} =1 \] v?

Answer 2

intercept

Answer 3

@Jonask is correct

Answer 4

do i sub (4,0) in ?

Answer 5

The foci are (plus/minus a*e,0) where the eccentricity

e = sqrt(1+ (b^2/a^2))

Answer 6

? what do i do what tiwtha

Answer 7

whats interecept??

Answer 8

foci, 4 = 4/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

Answer 9

can do intercept way??

Answer 10

What is "intercept way"? What intercept?

Answer 11

@Jonask ??

Answer 12

the intercept only works in an ellipse i thought you drew an ellipse

Answer 13

@estudier is correct

Answer 14

S/B

foci, 4 = 3/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

Answer 15

Can u do this? It is not difficult.

Answer 16

i think you can find by subbing in a point.. but i dunno which point

Answer 17

yeah but i dont think i can remember ..

Answer 18

can you find the corodinate of point directly above foci??

Answer 19

foci, 4 = 3/e -> e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2

So 4/3 = sqt(1 + b^2/3^2) -> b^2 = 12/9

Answer 20

yeah but i dont wanna remember that if in test -_-

Answer 21

they are related by a^2+b^2=c^2 as well right

Answer 22

U can say c^2 = a^2 -b^2 (same thing)

Answer 23

Actually, I made mistake in figures:

4/3 = sqrt(1 +b^2/3^2) -> 16/9 = 1 + b^2/3^2

-> 3^2 * 16/9 = 3^2 + b^2 -> b^2 = 3^2 (16/9 -1) = 3^2 *7/9 = 7

You can check it here

http://www.wolframalpha.com/input/?i=%28x^2%2F3^2%29++++-+y^2%2F7+%3D+1