Question

solve for x

Answer 1

a)\[\frac{ x^2-10x+15 }{ x^2-6x+15 }=\frac{ 3x }{ x^2-8x+15 }\]

Answer 2

how much could u solve ?

Answer 3

b)\[\frac{ 2x }{ 2x^2-5x+3 }+\frac{ 13x }{ 2x^2+x+3 }=6\]
either of them

Answer 4

i could substitute

Answer 5

\[x^2+15\]is everywhere

Answer 6

that won't help, i think....

Answer 7

all i know is that the expressions are common either by completing square or factorising

Answer 8

jitesh, did u already think about denom ?
its not factorizable , factoring won't help here

Answer 9

hmm.......

Answer 10

you can alsotry b)

Answer 11

u r right here @hartnn :)

Answer 12

well \[x^2-10x+15=(x^2-8x+15)-2x\]
\[x^2-6x+15=(x^2-8x+15)+2x\]

Answer 13

\[\frac{ p-2x }{ p+2x }=\frac{ 3x }{ p }\]

Answer 14

nice! jonask

Answer 15

\[p=x^2-8x+15\]

Answer 16

from here??

Answer 17

\[p^2-2px=3px+6x^2\]
\[p^2-5xp-6x^2=0\]

Answer 18

p^2 -6px +px-6x^2 =0

Answer 19

how

Answer 20

ohyes

Answer 21

(p-6x)(p+x)=0

Answer 22

\[\frac{ 2x }{ 2x^2-5x+3 }+\frac{ 13x }{ 2x^2+x+3 }=6\]\[\frac{2x}{2x^2+3x+2x+3}+\frac{13x}{2x^2+3x-2x+3}=6\]\[\frac{2x}{x(2x+3)+1(2x+3)}+\frac{13x}{}=6\] @hartnn can u help me factor \(2x^2+x+3\)???

Answer 23

looks adorable

Answer 24

\[p=6x,p=-x\]

Answer 25

jitesh, can't be factored

Answer 26

\[x^2-14x+15=0\]
and\[x^2-9x+15=0\]

Answer 27

jonask on right path, u'll get it now

Answer 28

put OR instead of AND

Answer 29

wait\[x^2-7x+15=0 \]
2nd 1

Answer 30

ok ! so both of this question can't be solved by factorization therefore we must use "completing the square" method.

Answer 31

-9x ? or -7x ?

Answer 32

-7x

Answer 33

noe @jiteshmeghwal9 can factor out

Answer 34

now

Answer 35

which one ?

Answer 36

u use the method, what jonask has done here

Answer 37

me ?

Answer 38

aaaargh.......it's puzzling :/

Answer 39

lol

Answer 40

seems like they cant factor

Answer 41

yeah, then maybe us formula

Answer 42

*use

Answer 43

\[x=\frac{ 14\pm \sqrt{14^2-4(15)} }{ 2 }\]
the other one is error

Answer 44

means complex roots

Answer 45

\[7\pm \sqrt{34}\]

Answer 46

for these one,what does wolfram say

Answer 47

b)

Answer 48

http://www.wolframalpha.com/input/?i=2x%2F%282x%5E2%E2%88%925x%2B3%29%2B13x%2F%282x2%2Bx%2B3%29%3D6

Answer 49

there is error somewhere

Answer 50

\[(x^2-10x+15)(x^2-8x+15)=3x(x^2-6x+15)\]\[x^4-8x^3+15x^2-10x^3+80x^2-150x+15x^2-120x+225=3x^3-18x^2+45x\]\[x^4-10x^3-8x^3+15x^2+80x^2+15x^2-120x+225=3x^3-18x^2+45x\]\[x^4-18x^3+110x^2-270x+225=3x^3-18x^2+45x\]\[x^4+225=3x^3+18x^3-18x^2-110x^2+220x+45x\]\[x^4+225=21x^3-128x^2+265x\]I did ths long hard work & gt this till here : & i don't know even it's right or nt :)

Answer 51

no error in 1st part
http://www.wolframalpha.com/input/?i=%28x%5E2%E2%88%9210x%2B15%29%2F%28x%5E2%E2%88%926x%2B15%29%3D3x%2F%28x%5E2%E2%88%928x%2B15%29
jitesh, when u started multiplying, u should have anticipated the fourth power of x coming....

Answer 52

i am confused wich one are we doing now ,is there previous one settled

Answer 53

\[\frac{ 2x }{ p }+\frac{ 13x }{ p-6x }=6\]
\[2px-12x^2+13xp=6p^2-36p\]
\[6p^2-15xp-36p+12x^2=0\]

Answer 54

\[6p^2+3p(5x-12)+12x^2=0\]

Answer 55

\[2p^2+p(5x+12)+4x^2=0\]

Answer 56

1st one was solved completely, right ?
now we are on 2nd, need to think different....

Answer 57

lets write it like the prev(1st one)

Answer 58

\[\frac{ 2x }{ 2x^2-5x+3 }=6-\frac{ 13x }{ 2x^2+x+3 }\]

Answer 59

\(2px-12x^2+13xp=6p^2-36px\)

Answer 60

hm i got x=3/4 or 2 or \[-\frac{9+-\sqrt{105}}{4} \]

Answer 61

crrect how

Answer 62

you did wrong in your step.. just continue from what hartnn wrote

Answer 63

\[2px−12x2+13xp=6p2−36p \] <-- wrong not -36p is +36px

Answer 64

yes but this does not help does it

Answer 65

-36px

Answer 66

u get \(2p^2+17px+4x^2=0\)
not factorizable, how did u get power?

Answer 67

oh its not p-6x its p+6x \[2x^2+x+3 = 2x^2-5x+3+6x \not -6x\]

Answer 68

the stuff below 13x in original

Answer 69

power??

Answer 70

aah!

Answer 71

no it works out if you fix that

Answer 72

\(\large \frac{ 2x }{ p }+\frac{ 13x }{ p+6x }=6\)

Answer 73

oh sorry about that

Answer 74

\[2px+12x^2+13px=6p^2+36px\]

Answer 75

\[6p^2+21px-12x^2=0\]
\[2p^2+7px-4x^2=(2p-x)(p+4x)\]

Answer 76

\[2(2x^2-5x+3)-x=0\] OR
\[2x^2-5x+3+4x=0\]

Answer 77

\[x=2OR4/3\]

Answer 78

4/3 or 3/4 ?

Answer 79

3/4

Answer 80

thanks @hartnn @powerangers69