Question

solve for x,techniques

Answer 1

\[\frac{ (x^2+x+1)^2 }{ (x^2+1)(x^2-x+1) }=\frac{ 1 }{ 3 }\]

Answer 2

\[x^3 \pm\ y^3=(x\pm\ y)(x^2\mp\ xy+y^2)\]

Answer 3

\[numerator=[\frac{ x^3-1 }{ x-1 }]^2\]
\[dinominator=[\frac{ x^3+1 }{ x+1 }]\times (x^2+1)\]

Answer 4

^ won't help much

Answer 5

\[3(x^2+x+1)=(x^2+1)(x^2-x+1)\]

Answer 6

let\[x^2+1=k\]
\[3(k+x)=k(k-x)\]
\[3k+3x=k^2-kx\]

Answer 7

\[k^2-k(x+3)-3x=0\]

Answer 8

forgot^2

Answer 9

\[3(k+x)^2=k^2-kx\]
\[3k^2-6kx+3x^2=k^2-kx\]
\[2k^2-5kx+3x^2=0\]

Answer 10

supposed to be\[2k^2+7xk+3x^2=0\]
\[(2k+x)(k+3x)=0\]

Answer 11

\[2x^2+2+x=0\] and \[x^2+3x+1=0\]

Answer 12

i didnt open +6kx not -6kx

Answer 13

oh, right

Answer 14

error

Answer 15

your last 2 equations are correct

Answer 16

u get real roots for x^2+3x+1=0

Answer 17

oh thanks