Question

The depth of water in a glass at each time is measured, as coloured water flowed in at a constant rate. The results are tabulated below:
T (s) V (mL)
10 2
20 2.6
30 3
40 3.3
50 3.5
60 3.7
70 3.9
80 4.1
90 4.3
100 4.4

1) Determine the depth of water in the glass as a function of time. Assume that depth at t=0 is 0cm.

2) Using geometry, determine a theoretical equation for the depth as a function of time.

Answer 1

Wouldn't you need to know the width of the glass?

Answer 2

I guess "V" is supposed to be depth.....

Answer 3

But V is in units of milliliters . . .

Answer 4

It can be done keeping the base area of the glass as a variable expression.
Maybe assume it is a cylinder and let r = radius?

Answer 5

the radius is 3.2cm and the depth is 4.8cm

Answer 6

@CliffSedge you just keep answering. you too are useless like me ... as you said me earlier, you could be suspended soon.

Answer 7

@soty2013 What?

Answer 8

A radius of 3.2 cm implies a base area of π(3.2)^2 cm^2.
Divide the volume by that area to get the height.

Answer 9

for the V(ml), it is meant to be D(cm)

Answer 10

Questions 1 and 2 seem to be the same question now....

From 40 to 90, depth goes up by 0.2 per 10 secs so if we take that as the "real" rate

Depth = 0.02t