Question

as easy as a,b,c

Answer 1

is that 3x^3 ?

Answer 2

if a,b,c are roots of \[3x^3-4x^2+7x-23=0\]
determine the value of\[a^2+b^2+c^2\]

Answer 3

know the formulas for sum of roots, product of roots...

Answer 4

@surdawi but you understand the question

Answer 5

no

Answer 6

\[(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)\]

Answer 7

yeah u'll have a+b+c and ab+bc+ac directly....

Answer 8

for an equation Ax^3+Bx^2+Cx+D=0
sum of roots = -B/A
product of roots = -D/A
and product od 2 roots at a time = C/A

Answer 9

last one always the same

Answer 10

c/a

Answer 11

last one ?

Answer 12

nomatter wich roots

Answer 13

product of 2 roots at a time = C/A

Answer 14

means is a,b,c are roots, ab+bc+ca = -C/A

Answer 15

okay

Answer 16

so now first find A,B,C,D...

Answer 17

A=3,B=-4,C=7,D=-23
\[a+b+c=\frac{ 4 }{ 3 }\]
\[ab+bc+ac=-\frac{ 7 }{ 3 }\]
\[abc=\frac{ -23 }{ 3 }\]
i ahve been using this formular unconciously,i never knew it was standard

Answer 18

ab+bc+ac = C/A = 7/3

Answer 19

\[a^2+b^2+c^2=(add)^2-2(product)\]

Answer 20

okay

Answer 21

\[=(4/3)^2-2(7/3)\]

Answer 22

that should be it...do u have answers to verify

Answer 23

no,i'll try to find later,i used to take the long way for this the rules help....great help

Answer 24

ok :)