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Mathematics 13 Online
OpenStudy (anonymous):

consider the natural basis for R4,and let W be spanned by {(1,-1,2,-3)(1,1,2,0)(3,-1,6,-6)} find the standard basis for W

OpenStudy (anonymous):

check P75 in the guide,

OpenStudy (anonymous):

If someone helps me then I will help them!

OpenStudy (anonymous):

@HorseCrazyGirlForever what kind of help do u want???

OpenStudy (anonymous):

Help with a measuring problem I just bumped my question.

OpenStudy (amistre64):

just row reduce the vectors and it will produce the standard vectors

OpenStudy (anonymous):

@matrix65 ......dnt hav a guide....just cut it and paste it here or email me on.......

OpenStudy (anonymous):

@amistre64 how??

OpenStudy (amistre64):

how to row reduce?

OpenStudy (amistre64):

row reduce is like chapter 1, basis is material that uses row reductions.

OpenStudy (anonymous):

that cant help..... that wont be a basis....@amistre64

OpenStudy (anonymous):

solution,..lol write the vectors in the spanning set as rows of a matrix: 1 -1 2 -3 1 1 2 0 3 -1 6 -6 reduced to Hermine normal form gives 1 0 2 -3/2 0 1 0 3/2 0 0 0 0 then a standard basis for W is given by the rows of the matrix i.e {(1;0;2;-3/2),(0;1;0;3/2)} is a standard basis for W w.r.t the natural basis for R4. NB: dim W=2

OpenStudy (amistre64):

if you take the three vectors, and augment them next to each of the standard R4 vectors, you can determine if the standard R4s can be created by the given vectors.

OpenStudy (anonymous):

@matrix65 gona nje.....r u done

OpenStudy (anonymous):

@msamido wat tym r we writing linear algebra, lol dats the ansa, wat else do u want. hahaha ga se nna ke guide ya Mr.T

OpenStudy (amistre64):

Wx=[1,0,0,0], if x = (W|[1,0,0,0]) has a solution. http://www.wolframalpha.com/input/?i=rref%7B%7B1%2C1%2C3%2C1%7D%2C%7B-1%2C1%2C-1%2C0%7D%2C%7B2%2C2%2C6%2C0%7D%2C%7B-3%2C0%2C6%2C0%7D%7D [1,0,0,0] cannot be formed and so is not in the span, nor can be used to produce any vector in W i believe 0,1,0,0 and 0,0,0,1 are the only 2 that are usable but then again, its been awhile since i tried working out this stuff :)

OpenStudy (anonymous):

@amistre64 they used Hermite's normal form method to reduce the matrix

OpenStudy (anonymous):

@matrix65 ...im not writtin ...thats y im stress less but u gonna write 14h00 on mondy

OpenStudy (amistre64):

then im sure the hermite will be effective ;)

OpenStudy (anonymous):

@amistre64 im gettin lost

OpenStudy (amistre64):

im not soo sure that I aint lost meself

OpenStudy (anonymous):

@matrix65 i 4gotten it just remmbr me a lil bit

OpenStudy (anonymous):

@msamido y u nt writing, lol stop joking please!

OpenStudy (anonymous):

im not .... but plz dnt tell any 1 coz im pretenting tht im writtin ...gore ke maizixe

OpenStudy (anonymous):

hahahaha lol people qualified with disdinctions, 98%,

OpenStudy (anonymous):

dnt tell any 1 plz it mst remain a c-cret between us

OpenStudy (anonymous):

i'll ckeck 2day ko notice board,lol i know ur student number*hides*

OpenStudy (anonymous):

wr dd u got my std no??

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