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MIT 6.002 Circuits and Electronics, Spring 2007 16 Online
OpenStudy (anonymous):

The elements in this circuit have the following values: R1=100Ω, R2=100Ω, R3=200Ω, V1=5V, I1=0.01A and I2=0.001A

OpenStudy (anonymous):

circuit:

OpenStudy (anonymous):

it is decided by finding the voltage of r1 r2 r3

OpenStudy (anonymous):

like v3=(.01-.001)*200 so power for r3=v3^2/r3

OpenStudy (anonymous):

a)Va=4.8 b)Vb=3.4 c)power across R1=0.0064 d)power across R2=0.0064 e)power across R3=0.0578 f)power from v1=0.085 g)power from I1=0.034 h)power from I2=-0.0034

OpenStudy (anonymous):

Va=4.8 power from v1=0.085 power from I2=-0.0034 these r wrong..............

OpenStudy (anonymous):

va=4.2 and power from voltage source is 0.057 and power from current source is the same may be try reversing the polarity

OpenStudy (anonymous):

v3=.0162

OpenStudy (anonymous):

k i got it.... thanks vipul n vivek...

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