OpenStudy (anonymous):

Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16. I am totally confused on this one, can someone explain what to do please?

4 years ago
OpenStudy (anonymous):

The rectangle area will be 4xy (take x, y as the point in the first quadrant) so A= xy = sqrt(16-16y^2)*y and now u have something to differentiate.

4 years ago