Question

Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown.

y = -3 halvesx
y = 3 halvesx - 6
y = -2/3x - 5/3
y = 2/3x - 13/3

Answer 1

@...help... please help me

Answer 2

I can try but I am not really sure :\ .....

Answer 3

k

Answer 4

where is the line and the point.
Are they in the attached file?

Answer 5

yes

Answer 6

Can you see these points on the equation of the line ?
(0, 3) and (-3, 1)

Answer 7

yes

Answer 8

thus the slope of the given line will be \[\Huge m=\frac{ 3-1 }{ 0-(-3) }=\frac{ 2 }{ 3 }\]

Answer 9

Now can you find the slope w/c is perpendicular to the above one?

Answer 10

you there?????

Answer 11

w/c ?

Answer 12

you there?????

Answer 13

@Zekarias

Answer 14

ok I am here
you have the slope of the given line, w/c is 2/3.
Now can you tell me the slope w/c is perpendicular to 2/3.

Answer 15

You know this?\[\Huge m{\times}m_{perpendicular} =-1\]

Answer 16

whats w/c

Answer 17

which....w/c

Answer 18

Thus the slope what I ask you before, anyhow, is\[\Huge m_{\perp}=\frac{ -1 }{ m }=\frac{ -1 }{ \frac{ 2 }{ 3 } }=\frac{ -3 }{ 2 }\]

Answer 19

Therefore finally we have slope (-3/2) and point (2, -3).
Finally\[\Huge \frac{ y-(-3) }{ x-2 }=\frac{ -3 }{ 2 }\]\[\Huge 2y+6=-3x+6\]

Answer 20

okay i see. uhm sorry but which choice would that be ?